Question

L

Find m/JKM.
70°
2x
(5x+1)
K
M
The measure of ZJKM is
O

Answer 1

116

Explanation:

∠JKM= 5X+1

∠JKM=(∠J+∠L)

5X+1= 2X+70

3X=69

X=23

∠JKM= 5X+1 = 5(23)+1 = 116

Answer 2

116

Explanation:

Using the exterior angle theorem,

`2x+70=5x+1 \\ \\ 70=3x+1 \\ \\ 3x=69 \\ \\ x=23 \\ \\ m\angle JKM=5(23)+1=116^(\circ)`