Final answer:
Mathematics problem-solving uses the given percentage to calculate the expected number of crookedly parked cars out of 22, yielding 8.25 cars (Answer A). But, the calculation of the probability for at least 10 crookedly parked cars is unclear without further information.
Step-by-step explanation:
The subject of this question is Mathematics, specifically focusing on probability and statistics. The student's question regarding angle parking is directly related to a conceptual learning scenario used to teach these concepts.
For the given scenario, where 37.5% of cars in a parking lot are parked crookedly, we can calculate the expected number of crookedly parked cars out of a sample of 22. Using the percentage, we find that 37.5% of 22 cars is 8.25 cars, which is answer A. This calculation uses basic proportionality.
For calculating the probability that at least 10 of the 22 cars are parked crookedly, we would typically use the binomial probability formula. However, as the exact probability is not provided in the choices, it seems there might be a typo in the question. None of the options matches the probable correct probability. Therefore, I would need more information or clarification to provide the correct choice between A or B for this part of the question.
Campus parking and the efficiency and arrangement of parking can greatly impact daily life for students and faculty. Addressing such practical issues involves not only mathematical calculations but also an understanding of urban planning and logistic concerns.