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Question 5

2 pts
How many atoms of helium are found in a helium balloon if it has 3.9g of helium
inside?
The answer should be
x1023
Type the number that precedes the x1023

User Dimskiy
by
5.6k points

1 Answer

3 votes

Answer: There are
6.2* 10^(23) atoms of helium are found in a helium balloon if it has 3.9 g of helium inside.

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number
6.023* 10^(23) of particles.

To calculate the moles, we use the equation:


\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}=(3.9g)/(4.00g/mol)=0.975moles

1 mole of helium contains =
6.023* 10^(23) atoms

Thus 0.975 moles of helium contain =
(6.023* 10^(23))/(1)* 0.975=6.2* 10^(23) atoms

User Julio Feferman
by
5.3k points