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The perimeter of a rectangle is 44 meters and the length is 10 meters more than twice the width. Find the dimensions.

User Tobias Wollgam
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1 Answer

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14 votes
Given: First understand the problem

Width(W) = X

Length (L) = 2X + 2

Perimeter: 44 m - a rectangle

Find: L & W

Plan:

Use the Perimeter formula to get an equation to solve.

Always try and find an equation relating the given facts to what must be found.

P = 2(L + W) Now substitute & solve

44 = 2((2X + 2) + X) = 4X + 4 + 2X = 6X + 4 Remove parentheses and combine like terms

Therefore: 6X + 4 = 44 Subtract 4 from both sides of the equation.

6X = 40 Divide both sides of the equation by 6

X = 40/6 ≈ 6.666…

Thus: W = 6.666…m, L = 2X + 2 ≈ 2(6.666) + 2 = 15.332 m
User Coding Active
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