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Can you solve this?? kinda an emergency (the answer is an percentage)

Can you solve this?? kinda an emergency (the answer is an percentage)-example-1

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The conditional probabilities are calculated as:

1) P(A or B) = 100%

2) p(A and B) = 0.2331

3) P(A | B) = 0.63

4) P(not B | not A) = 0

How to find the conditional probability?

1) p(A or B) = p(A) + p(B).

We have:

p(A) = 63/100 = 0.63

P(B) = 37/100 = 0.37

Thus:

P(A or B) = 0.63 + 0.37 = 100%

2) p(A and B) = p(A) * p(B)

p(A and B) = 0.63 * 0.37

p(A and B) = 0.2331

3) P(A | B) = P(A ∩ B)/P(B)

P(A | B) = 0.2331/0.37

P(A | B) = 0.63

4) P(not B | not A) = 0

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