214k views
2 votes
Find an equation of the line that contains the point (-1,3) and is parallel to the line x+3y=6.

HELP PLSS I REALLY NEED IT

User Thasmo
by
7.8k points

2 Answers

9 votes

Answer:

x - 8 = -3y

Step-by-step explanation:

x + 3y = 6

Convert to y = mx + b form, and we get: x - 6 = -3y

Remember m is our slope, and in this case, it is simply one.

Because the line we're solving for is parallel, it must have the same slope.

y = 1x + b, we just have to solve for b now.

This is done by plugging in our points, which looks like: -1 + b = -3 x 3

simplify: -1 + b = -9, b = -8

Combining what we know yields: x - 8 = -3y

Hope this helps :)

User Amod
by
7.8k points
9 votes

Answer:

Explanation:

3y = -x + 6

y = -1/3x + 2

y - 3 = -1/3(x + 1)

y - 9/3 = -1/3x - 1/3

y = -1/3x + 8/3

User Pharaoh
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories