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Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a

diameter of 8 feet and a height of 11 feet. Container B has a diameter of 6 feet and a height of 18 feet.
Container A is full of water and the water is pumped into Container B until Container B is completely full.
After the pumping is complete, what is the volume of the empty space inside Container A, to the nearest
tenth of a cubic foot?

User Lolbas
by
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1 Answer

1 vote

The volume of the empty space inside Container A is approximately 298.5 cubic feet (rounded to the nearest tenth).

The volume V of a cylinder is given by the formula
\(V = \pi r^2 h\)

For Container A:


\[ V_A = \pi * (4^2) * 11 \]

For Container B:


\[ V_B = \pi * (3^2) * 18 \]

Now, calculate the volumes:


\[ V_A \approx 452.38934 \text{ cubic feet} \]


\[ V_B \approx 153.93804 \text{ cubic feet} \]

The empty space inside Container A is then the difference:

Empty space} =
V_A - V_B

Empty space
\approx 452.38934 - 153.93804

Empty space
\approx 298.4513 cubic feet

So, the volume of the empty space inside Container A is approximately 298.5 cubic feet (rounded to the nearest tenth).

User Xiawei Zhang
by
8.1k points

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