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Diego begins the summer with a savings of $ 75.00 more than Nicole. Diego’s job pays $9.75 per hour. Nicole’s job pays $11.25 per hour. If they both work the same amount of time each day how many hours of work will it take Nicole to have at least as much money as Diego? Write an inequality than solve

Diego begins the summer with a savings of $ 75.00 more than Nicole. Diego’s job pays-example-1

1 Answer

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Final answer:

Nicole will need to work at least 50 hours to have at least as much money as Diego.

Step-by-step explanation:

To find how many hours of work it will take Nicole to have at least as much money as Diego, we need to set up an inequality. We know that Diego begins with $75.00 more than Nicole, so we can set up the inequality as follows:

9.75x + 75 ≤ 11.25x

where x is the number of hours they both work. Now we can solve for x:

9.75x + 75 ≤ 11.25x

75 ≤ 11.25x - 9.75x

75 ≤ 1.5x

50 ≤ x

So it will take at least 50 hours of work for Nicole to have as much money as Diego.