Answer:
Given, initial velocity, u=0m/s and final velocity v=65m/s
Acceleration a=3m/s
2
If d be the allowed length for the runway.
Using formula v
−u
=2aS
(65)
−0
=2(3)d
⟹ d=65
/6=704.16∼704m
8.8m questions
11.4m answers