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The value of (1-w) (1-w*2) , where w is the cube root of the complex number is?

User Zozo
by
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1 Answer

9 votes

Answer:

3

Explanation:

1+ω+w²=0

ω³=1

(1-ω)(1-ω²)=1-ω²-ω+ω³

=1-ω-ω²+1

=2+1-1-ω-ω²

=3-(1+ω+ω²)

=3-0

=3

User Joe Volcano
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