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Factor f(x) = 4x2 + 11x? - 104x + 105 into linear factors given that – 7 is a zero of f(x).

f(x) = 4x + 11x2 - 104x + 105 = |
(Factor completely.)

Factor f(x) = 4x2 + 11x? - 104x + 105 into linear factors given that – 7 is a zero-example-1
User WLGfx
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1 Answer

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Answer:

f(x) = 4x + 11x2 - 104x + 105 = (x - 3)(x + 7)(4x - 5)

Explanation:

f(x) = 4x^3 + 11x2 - 104x + 105

has the coefficients {4, 11 -104, 105}. We perform synthetic division using the given -7 as divisor:

-7 / 4 11 -104 105

-28 119 -105

-----------------------------------

4 -17 15 0

Since the remainder is zero (0), we have shown that -7 is a zero of f(x). The coefficients of the quotient (above) are {4, -17, 15}. Let's try factoring the corresponding polynomial again using synthetic division. Start out by using 5 as divisor and determining whether or not the remaindeer is zero:

5 / 4 -17 15

20 15

-------------------------

4 3 30 No, the remainder is 30 and so 5 is not a

root of this quadratic. Try the divisor 3 instead:

3 / 4 -17 15

12 -15

---------------------------

4 -5 0 Yes, the remainder is 0 and so 3 is a root.

Thus, the given f(x) = 4x + 11x2 - 104x + 105 factors as follows:

f(x) = 4x + 11x2 - 104x + 105 = (x - 3)(x + 7)(4x - 5). Notice that the coefficients of the last factor come from those we found above when using 3 as a divisor in synthetic division.

User Dinya
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