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Calculate the formula mass for each of the following compounds.

Part A
AgCl
Express your answer using two decimal places.

Part B
PBr3..... (small subscripts)
Express your answer using two decimal places.

Part C
CH3CONH2..... (small subscripts)
Express your answer using two decimal places.


Part D
Na3PO4..... (small subscripts)
Express your answer using two decimal places.

User Jamin
by
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1 Answer

4 votes

Final answer:

The formula masses are calculated by adding the atomic masses of the elements in each compound. AgCl has a formula mass of 143.32 amu, PBr3 is 270.67 amu, CH3CONH2 (acetamide) is 59.07 amu, and Na3PO4 is 163.94 amu.

Step-by-step explanation:

To calculate the formula mass (also known as molecular weight) of a compound, we sum the atomic masses of the elements constituting the compound, according to their respective numbers in the formula. Here's how to calculate the formula mass for each compound listed:

Part A: AgCl

Ag (Silver) = 107.87 amu (atomic mass units)
Cl (Chlorine) = 35.45 amu

Formula mass of AgCl = 107.87 + 35.45 = 143.32 amu

Part B: PBr3

P (Phosphorus) = 30.97 amu
Br (Bromine) = 79.90 amu (Each Br, Total 3 Brs)

Formula mass of PBr3 = 30.97 + 79.90*3 = 270.67 amu

Part C: CH3CONH2

This is the formula for acetamide. To calculate its formula mass:
C (Carbon) = 12.01 amu (3 times)
H (Hydrogen) = 1.01 amu (6 times)
O (Oxygen) = 16.00 amu
N (Nitrogen) = 14.01 amu

Formula mass of CH3CONH2 = 12.01*3 + 1.01*6 + 16.00 + 14.01 = 59.07 amu

Part D: Na3PO4

Na (Sodium) = 22.99 amu (3 times)
P (Phosphorus) = 30.97 amu
O (Oxygen) = 16.00 amu (4 times)

Formula mass of Na3PO4 = 22.99*3 + 30.97 + 16.00*4 = 163.94 amu

User Dmcb
by
8.4k points