Final answer:
The ionic compound SnBr4 is named tin(IV) bromide.
Step-by-step explanation:
When naming ionic compounds, we need to identify the cation (positive ion) and the anion (negative ion) present in the compound. In the case of SnBr4, the Sn represents the cation and the Br represents the anion. The cation is tin(IV) and the anion is bromide. When combined, the compound is named tin(IV) bromide.