Final answer:
The name of the ionic compound SnI4 is tin(IV) iodide.
Step-by-step explanation:
To name the ionic compound SnI4, we need to determine the names of the cation and anion. Sn represents the element tin, and I represents the element iodine. Tin is a transition metal that can have multiple charges, so we need to use the Stock system of nomenclature. The Stock system involves using Roman numerals to indicate the charge of the cation. In this case, Sn has a charge of 4, so the name of the cation is tin(IV). Iodine is a nonmetal, so we use the stem of its name and add the suffix -ide. Therefore, the name of the anion is iodide. Combining the names, we get tin(IV) iodide.