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"On the basis of periodic trends, determine the element in each pair with the higher first ionization energy (if possible).

Sn or I

a.Sn
b.I
c.It is impossible to determine based on periodic trends alone.

User GrahamMc
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1 Answer

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Final answer:

Based on periodic trends, tin (Sn) will have a higher first ionization energy compared to iodine (I).

Step-by-step explanation:

Based on periodic trends, we can determine the element with the higher first ionization energy. The ionization energy generally increases from left to right across a period and decreases from top to bottom within a group in the periodic table. In this case, we need to compare tin (Sn) and iodine (I). Tin is located to the left of iodine in Period 5, so it has a lower atomic number. Therefore, tin (Sn) will have a higher first ionization energy compared to iodine (I).

User Austin Wang
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