140k views
5 votes
A1= 5 a2= x a3= 45, what is x?

User NateW
by
8.1k points

1 Answer

7 votes
It seems like you're referring to a sequence where "a1" is the first term, "a2" is the second term, and so on. If we assume that the sequence is arithmetic (each term is obtained by adding a fixed number to the previous term), we can find the value of "x" by calculating the common difference between consecutive terms.

Given:
a1 = 5
a2 = x
a3 = 45

In an arithmetic sequence, the common difference (d) can be found using the formula:
d = a2 - a1

Substituting the given values:
d = x - 5

We can also express a3 in terms of a1 and the common difference:
a3 = a1 + 2d
45 = 5 + 2d

Solving for d:
2d = 45 - 5
2d = 40
d = 20

Now that we have the common difference, we can find the value of "x":
x = a1 + d
x = 5 + 20
x = 25

So, in this arithmetic sequence, if a1 = 5 and a3 = 45, then a2 is 25.
User Sharone
by
8.1k points