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A Mo/Tc generator has an elution efficiency of 89%. if 1.1 Ci of Tc is present on the column, what is the estimated activity of eluate that will be obtained?

a. 97.9 Ci
b. 979 mCi
c. 979 uCi
d. 97.9 mCi

User V Maharajh
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1 Answer

4 votes

Final answer:

The estimated activity of the eluate from a Mo/Tc generator can be calculated by multiplying the initial activity of Tc by the elution efficiency.

Step-by-step explanation:

The elution efficiency of a Mo/Tc generator is given as 89%. This means that 89% of the Tc-99 present on the column will be obtained in the eluate. If 1.1 Ci of Tc is present on the column, we can calculate the estimated activity of the eluate by multiplying 1.1 Ci by the elution efficiency: 1.1 Ci * 0.89 = 0.979 Ci.

User Sergiu Todirascu
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