Question

If dipyridamole is supplied in a 50ml vial containing 250 mg and a patient weighs 205 lb, how much volume will be needed from the vial to prepare his dose of 0.56 mg/kg?

a. 5.6
b. 10.4
c. 15.9
d. 22.6

Answer 1

To calculate the volume needed from the vial of dipyridamole, first convert the patient's weight to kilograms, calculate the total dose in milligrams, and then use a proportion to find the volume. The patient would need approximately 10.4 ml of dipyridamole.

Step-by-step explanation:

To calculate the volume of dipyridamole needed for a patient weighing 205 pounds at a dose of 0.56 mg/kg, first, convert the patient's weight to kilograms by dividing by 2.2 (1 kg = 2.2 lbs):

205 lbs ÷ 2.2 = 93.18 kg (approximately).

Next, calculate the total dose required in milligrams (mg):

0.56 mg/kg × 93.18 kg = 52.18 mg.

Now, determine how much volume is required from the vial that contains 250 mg in 50 ml:

Since 250 mg is to 50 ml as 52.18 mg is to X ml, you can set up a proportion:

(250 mg / 50 ml) = (52.18 mg / X ml).

Solve for X:

X = (52.18 mg × 50 ml) / 250 mg = 10.436 ml.

Therefore, the volume needed from the vial is approximately 10.436 ml, which when rounded to one decimal place is 10.4 ml.