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User Selay
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Sum of Interior angles of a Pentagon is 540°


\\ \tt\hookrightarrow 95+3x+23+90+7x-4+9x-6=540


\\ \tt\hookrightarrow 3x+7x+9x+95+90+23-4-6=540


\\ \tt\hookrightarrow 19x+198=540


\\ \tt\hookrightarrow 19x=540-198


\\ \tt\hookrightarrow 19x=342


\\ \tt\hookrightarrow x=(342)/(19)


\\ \tt\hookrightarrow x=18

User Andrew Jaffe
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14 votes

Answer:

  • x = 18

Explanation:

Sum of interior angles of the pentagon is:

  • 3x + 23 + 9x - 6 + 7x - 4 + 95 + 90 = 180(5 - 2)
  • 19x + 198 = 540
  • 19x = 342
  • x = 342/19
  • x = 18
User Nate Lee
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