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Acute inferior MI

-ST elevation in the inferior leads II, III and aVF
-reciprocal ST depression in the anterior leads

User Shimshon
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1 Answer

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Final answer:

a. An acute inferior myocardial infarction (MI) is typically identified through changes in the electrocardiogram (ECG) specifically ST elevation in leads II, III, and aVF which represent the inferior part of the heart.

b. Reciprocal ST depression can be seen in the anterior leads and is indicative of ischemia in the opposing area of the heart.

Step-by-step explanation:

An acute inferior myocardial infarction (MI) is identified by ST elevation in specific ECG leads and elevated markers like creatine kinase MB and cardiac troponin. An ECG displays the complex electrical activity of the heart, and several symptoms can indicate an MI, though some cases may be asymptomatic. Blood tests like creatine kinase MB and cardiac troponin are common indicators of myocardial injury, rising when cardiac muscle cells are damaged.

Analyzing an ECG involves understanding the intricacies of the heart's electrical activity, like the size and duration of electrical variations, and a vector analysis of cardiac function. An MI can cause typical ECG changes such as ST-segment elevation, among other findings. Echocardiography or cardiac magnetic resonance imaging can also be used to aid in the diagnosis.

Symptoms of an acute MI may include retrosternal pain, commonly known as angina pectoris, that often radiates down the left arm in males, shortness of breath, irregular heartbeat, nausea and vomiting, and sweating. However, symptoms can vary greatly between individuals, with a significant percentage of MIs presenting without any symptoms at all. Hence, a differential diagnosis is crucial.

User Martin Cazares
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