Question

A person is running at an initial velocity of 3.7 m/s. If the person is accelerating at 2 m/s2, what is their final velocity after 3 seconds?

Answer 1

9.7m/s

Step-by-step explanation:

`\pink{\frak{Given}}\begin{cases} \textsf{ Initial velocity of a person is 3.7m/s .}\\\textsf{The acceleration of the person is 2m/s$^2$ .} \end{cases}`

And we need to find out the velocity of the person after 3 seconds . Here we can use the First equation of motion namely ,

`\sf \longrightarrow v = u + at \\`

Where ,

• v is the final velocity .
• u is the initial velocity .
• a is the acceleration .
• t is the time taken .

Now substitute the respective values in the given equation ,

`\sf \longrightarrow v = 3.7m/s + 2m/s^2*3s\\`

Simplify ,

`\sf \longrightarrow v = 3.7m/s + 6m/s\\`

`\sf \longrightarrow \boxed{\bf velocity_(After\ 3 \ s )= 9.7 m/s}\\`

Hence the velocity after 3 seconds is 9.7 m/s .

Answer 2

9.7 ms⁻¹

Step-by-step explanation:

The formula to find the acceleration is :

`Acceleration=(Final \:Velocity-Initial\:Velocity)/(Time)`

According to the question, we are asked to find the Final Velocity.

For that, let the Final Velocity be x.

`Acceleration=(Final \:Velocity-Initial\:Velocity)/(Time)`

`2m/s^(2) =(x-3.7m/s)/(3 s)\\`

`2 =(x-3.7)/(3 )\\`

`2*3=x-3.7`

`6=x-3.7`

`6+3.7=x`

`9.7=x`

Therefore,

Final velocity = 9.7ms⁻¹

Hope this helps you :-)

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