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How many milliliters of a 20% magnesium sulfate solution are required to contain 40 grams of magnesium sulfate?

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Final answer:

To obtain 40 grams of magnesium sulfate from a 20% solution, you need 200 milliliters of the solution.

Step-by-step explanation:

To calculate the milliliters of a 20% magnesium sulfate solution needed to obtain 40 grams of magnesium sulfate, you can use the formula for percent concentration: percent concentration = (mass of solute / volume of solution) × 100. In this case, the concentration is 20%, and the mass of magnesium sulfate is 40 grams. To find the volume (V) in milliliters (mL) that contains 40 grams of magnesium sulfate in a 20% solution, you would set up the equation like this:

20% = (40g / V) × 100

To solve for V, rearrange the equation:

20 / 100 = 40g / V

V = 40g / (20 / 100)

V = 40g / 0.2

V = 200 mL

Therefore, 200 milliliters of a 20% magnesium sulfate solution are required to contain 40 grams of magnesium sulfate.

User Ven Nilson
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