Question

A student increases the temperature of a 200 cm balloon from 60°C to 120°C.

What will the new volume of the balloon be?
A)100cm^3
B)200cm^3
C)263cm^3
D)400cm^3

Answer 1

236 cubic cm

Step-by-step explanation:

We are given that

Initial volume, V1=200 cubic centimeter

Initial temperature, T1=60 degree Celsius=60+273=333 K

Final temperature, T2=120 degree Celsius=120+273=393 K

Kelvin temperature=Celsius temperature+273

We have to find the new volume of the balloon.

We know that

Charles's law

`(V_1)/(T_1)=(V_2)/(T_2)`

Using the formula

`(200)/(333)=(V_2)/(393)`

`V_2=(200* 393)/(333)`

`V_2=236cm^3`

Hence, the new volume of the balloon will be 236 cubic cm.