72.3k views
19 votes
1. Find the factored form of f(x) given it has x-intercepts (-3,0) and (4,0) and f(1)= -6. 2. Find the equation for f(x) given that it has roots of 2 and -3 and f(0)=12. Please someone help

User Foster
by
8.3k points

1 Answer

6 votes

Answer:

1) f(x) = 0.5*(x + 3)*(x - 4)

2) f(x) = -2*x^2 - 2*x + 12

Explanation:

Wen we have a quadratic function like:

f(x) = a*x^2 + b*x + c*x

And it has roots at x1 and x2, we can write the function in the factored form as:

f(x) = a*(x - x1)*(x - x2)

then:

1) we have x-intercepts at: (-3, 0) and (4, 0) (then the roots of this function are x = -3 and x =4) and we know that f(1) = -6

we have:

x1 = -3

x2 = 4

then we can write f(x) as:

f(x) = a*(x - (-3))*(x - 4)

f(x) = a*(x + 3)*(x - 4)

Where a is a real number.

and now we can use the fact that f(1) = -6

then:

f(1) = a*(1 + 3)*(1 - 4) = -6

a*4*(-3) = -6

a*-12 = -6

a = -6/-12 = 1/2 = 0.5

Then the function is:

f(x) = 0.5*(x + 3)*(x - 4)

2) Now we have roots x = 2 and x = .3

Then:

x1 = 2

x2 = -3

Then this function is something like:

f(x) = a*(x - 2)*(x - (-3))

f(x) = a*(x - 2)*(x + 3)

Now we know that f(0) = 12.

then:

f(0) = a*(0 - 2)*(0 + 3) = 12

a*(-2)*3 = 12

a*(-6) = 12

a = 12/-6 = -2

f(x) = -2*(x - 2)*(x + 3)

And we do not want this one written in factored form, so we can just distribute the multiplications to et:

f(x) = -2*(x - 2)*(x + 3) = (-2*x + 4)*(x + 3) = -2*x^2 + 4*x - 6*x + 12

f(x) = -2*x^2 - 2*x + 12

User Arnab Rahman
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories