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How many liters of 70% acid solution must be mixed with a 15% acid solution to get 550L of a 60% acid solution

User Shadeglare
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1 Answer

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Answer:

450 L

Explanation:

Let x represent the number of liters of 70% solution needed. Then the amount of 15% solution needed is (550-x), and the total amount of acid in the mixture is ...

0.70x + 0.15(550-x) = 0.60(550)

0.55x + 82.5 = 330 . . . . simplify

0.55x = 247.5 . . . . . . . . . subtract 82.5

x = 450 . . . . . . . . . . . divide by 0.55

450 liters of 70% acid solution must be used.

User Freewalker
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