Question

A father was 3 times as old as his son in 2052 B.S. and 5/3 times as old in 2080 B.S. in which year was the son born?​

Answer 1

The son was 14 years old in 2052 B.S. Solving the given conditions provided his age, which led to determining that the son was born in 2038 B.S.

Let's assume the son's age in 2052 B.S. is x years. Therefore, the father's age at that time was 3x years. By 2080 B.S., which is 28 years later, the son's age would be
`x + 28 years`, and the father's age would be
`3x + 28 years`. According to the second condition, the father is
`(5)/(3)` times as old as his son in 2080 B.S.

So, we can write the equation:
`3x + 28 = (5)/(3) (x + 28)`. Simplifying this equation, we get
`9x + 84 = 5x + 140`. Subtracting 5x and 84 from both sides, we get
`4x = 56`, which gives us
`x = 14`. Hence, the son was 14 years old in 2052 B.S. To find out the year he was born, we subtract his age from 2052 B.S, which means he was born in 2038 B.S.