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Help, due tonight (2/19/2021) at 11:59pm!

Help, due tonight (2/19/2021) at 11:59pm!-example-1
User Geremia
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1 Answer

8 votes

Answer:

283549.68 J

Step-by-step explanation:

From the question given above, the following data were obtained:

Mass (M) = 2.7 Kg

Initial Temperature (T₁) = 5.4 °C

Final temperature (T₂) = 30.5 °C

Specific heat capacity (C) = 4184 J/KgºC

Heat (Q) =?

The amount of heat energy needed can be obtained as follow:

Q = MC(T₂ – T₁)

Q = 2.7 × 4184 × (30.5 – 5.4)

Q = 11296.8 × 25.1

Q = 283549.68 J

Thus, the heat energy needed is 283549.68 J

User Merissa
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