Question

A weight hangs motionless from a spring, with a spring constant of 75 N/m. The spring stretched from its original length by 0.333 meters. How much weight hangs from the spring?

Answer 1

Step-by-step explanation:

Since the weight hangs motionless from the spring, the weight is not in motion and is balanced from vertical components of force ( the spring force and the mg of the weight) so

`f _s = mg`

where f s is the force of the spring.

Now, we can use Hooke Law

`f _(s) = kx`

where k is the spring constant and x is the displacement of length the spring is stretched.

We know that mg=fs so

`mg = kx`

mg=w so

`w = kx`

k is 75 and x is 0.333

so

`x = 75 \: (n)/(m) * 0.33 \: m`

`x = 24.975 \: n`

or

25 N or 24.98 N