173k views
1 vote
A parabola opening up or down has vertex (0,– 2) and passes through (12,16). Write its equation in vertex form.

User Zzxyz
by
7.9k points

1 Answer

5 votes

Final answer:

The equation of the given parabola in vertex form is y = 1/8x^2 - 2.

Step-by-step explanation:

To write the equation of a parabola in vertex form, we use the formula y = a(x-h)^2 + k, where (h, k) is the vertex of the parabola.

Given that the vertex is (0, -2), we substitute h = 0 and k = -2 into the equation and get y = a(x-0)^2 - 2 or y = ax^2-2.

To determine the value of 'a', we substitute the coordinates of the point (12, 16) into the equation:

16 = a(12)^2 - 2

16 = 144a - 2

144a = 18

a = 18/144 = 1/8

Therefore, the equation of the parabola in vertex form is y = 1/8x^2 - 2.

User CBono
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories