Question

Which of the following reflects the correct number of moles of P4010, produced in the presence of 10 mol of molecular oxygen (02) and an unlimited number of moles phosphorous according to : P4(s) 502(9) → P4010(5)

Answer 1

In a chemical reaction with 10 moles of O2 and an unlimited number of moles of P4, the reaction P4 + 5O2 → P4O10 will produce 2 moles of P4O10, as only 2 moles of O2 are required for each mole of P4.

Step-by-step explanation:

The question asks about the correct number of moles of P4O10 produced when 10 moles of molecular oxygen (O2) react with an unlimited supply of phosphorous according to the reaction equation P4(s) + 5O2(g) → P4O10(s).

Based on the stoichiometry of the reaction, 1 mole of P4 reacts with 5 moles of O2 to produce 1 mole of P4O10.

Since O2 is present in excess quantity (10 moles available, but only 2 moles are required to produce 1 mole of P4O10 with the available P4), the amount of P4 will be the limiting factor.

Thus, 2 moles of P4O10 will be produced.