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A muscle builder holds the end of a massless rope. At the center of the rope, a 7.9 kg ball is hanging. If the angles made by the the muscle builder's arms are both 6 degrees, what is the tension in the rope?

A) 960 N
B) 740 N
C) 370 N
D) 230 N
E) 150 N

User Mixel
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1 Answer

6 votes

Final answer:

The tension in the rope is 77.42 N.

Step-by-step explanation:

To find the tension in the rope, we can use the principles of equilibrium. Since the rope is massless and the ball is in equilibrium, the tension in the rope will be equal to the weight of the ball. The weight of an object is given by the equation: weight = mass * acceleration due to gravity. In this case, the weight of the ball is calculated as: weight = mass * acceleration due to gravity = 7.9 kg * 9.8 m/s^2 = 77.42 N. Therefore, the tension in the rope is 77.42 N. The question involves calculating the tension in the rope when a muscle builder holds the end of a massless rope with a ball hanging from its center. Given the angles made by the builder's arms and the mass of the ball, we can use the concept of equilibrium and force components to find the tension in each half of the rope, which will be equal due to symmetry and the massless ness of the rope.

User Omkar T
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