Question

42.10 g of Br₂ =
atoms

Answer 1

The number of atoms present in 42.10 grams of bromine gas, Br₂ is
`\underline{1.57*10^(23)}\ atoms`

How to calculate the number of atoms of bromine gas, Br₂?

The number of atoms present in 42.10 grams of bromine gas, Br₂ can be calculated as shown below:

• Mass of bromine gas, Br₂ given (m) = 42.10 grams
• Molar mass of bromine gas, Br₂ (M) = 159.808 g/mol
• Mole of bromine gas, Br₂ present = m / M = 42.10 / 159.808 = 0.26 mole
• Avogadro's constant =
  `6.022*10^(23)`
• Number of atoms of bromine gas, Br₂ present =?

Number of atoms of bromine gas, Br₂ present = Mole × Avogadro's constant

= 0.26 ×
`6.022*10^(23)` =
`1.57*10^(23)\ atoms`

From the above calculation, we can conclude that the number of atoms present in 42.10 grams of bromine gas, Br₂ is
`1.57*10^(23)\ atoms`

Complete question:

How many atoms are present in 42.10 g of bromine gas?

42.10 g of Br₂ = ____atoms