Final answer:
To increase the temperature of 50 grams of water by 2°C, we would need to input 418.4 joules of heat energy.
Step-by-step explanation:
To increase the temperature of 50 grams of water by 2°C, we need to calculate the amount of heat energy required. The formula for calculating heat energy is q = m * C * ΔT, where q is the heat energy, m is the mass of the substance (in this case, water), C is the specific heat capacity of the substance, and ΔT is the change in temperature.
Considering the specific heat capacity of water is approximately 4.184 J/g°C, we can calculate the heat energy as follows: q = 50 g * 4.184 J/g°C * 2°C = 418.4 J.
Therefore, it would require 418.4 joules of heat energy to increase the temperature of 50 grams of water by 2°C.