Question

12 G of carbon react with 16 G of oxygen how much carbon monoxide is formed ​

Answer 1

28 g CO

Step-by-step explanation:

First convert grams to moles.

1 mole C = 12.011 g (I'm just going to round to 12 for the sake of this problem)

12 g C •
`(1 mol C)/(12 g C)` = 1 mol C

1 mol O = 15.996 g (I'm just going to round to 16)

16 g O •
`(1 mol O)/(16 g O)` = 1 mol O

So the unbalanced equation is:

`C + O_(2)` ->
`CO` (the oxygen has a 2 subscript because it is part of HONClBrIF meaning when not in a compound these elements appear in pairs - called diatomic elements)

The balanced equation is:

`2 C + O_2` ->
`2 CO`

However, carbon is the limiting reactant in this equation and two moles cannot react because only 12 g (1 mole) are present. Therefore, use the equation

`C + (1)/(2) O_2` ->
`CO`.

1 mole of CO is formed, therefore 12 g + 16 g = 28 g CO.