Answer:
Explanation:
If the sumof two numbers is 4 and the sum of their squarea minus three times their product is 76, find the two numbers
Let us represent:.
First number = x
Second number = y
If the sum of two numbers is 4
= x + y = 4
x = 4 - y
The sum of their squares minus three times their product is 76
x² + y² - 3xy = 76
We substitute 4- y for x
(4 - y)² + y² - 3(4 - y)y = 76
(4 - y)(4 - y) + y² - (12 - 3y)y = 76
16 - 4y - 4y - y² + y² - 12y - 3y² = 76
16 -20y - 3y² = 76
3y² + 20y - 16 + 76 = 0
3y² + 20y + 60 = 0