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8 votes
Solve for x to the nearest tenth.

please help i’m failing

Solve for x to the nearest tenth. please help i’m failing-example-1
User Kocka
by
7.5k points

2 Answers

5 votes

Answer:

x≈ 8.3

Explanation:

ok first you have to find the hypotenuse of the smaller triangle

a²+b²=c²

2²+4²=c²

4+16=20

√20≈ 4.5

4.5²+7²=c²

20.25+49≈ 69.25

√69.25≈ 8.3

User Div
by
7.1k points
5 votes

Answer:

x =
√(69)

Explanation:

Pythagorean theorem: A^2 + B^2 = C^2

first, find the length of the line cutting through the shape:

let's call this line L.

plug the numbers into the theorem.

4^2 + 2^2 = L^2

16 + 4 = L^2

20 = L^2

next, plug 7 and L into the theorem again to find x

L^2 + 7^2 = x^2

20 + 49 = x^2

69 = x ^2

x =
√(69)

User Umbriel
by
8.2k points

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