Question

Can u solve this and explain how to do it pls?

Answer 1

Answer:
`6y^(-1)`

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Step-by-step explanation

The coefficients 3 and 2 multiply to 6. This is the value of k when they mentioned the format
`k\cdot y^n`

The cube root is the same as having an exponent of 1/3.

`\sqrt[3]{y} = y^(1/3)`

This is useful because we'll need to apply this rule

`a^b\cdot a^c = a^(b+c)`

to be able to say:

`y^(-4/3)\cdot y^(1/3) = y^(-4/3+1/3) = y^(-3/3) = y^(-1)`

In short,

`y^(-4/3)\cdot y^(1/3) = y^(-1)`

which is the same as saying

`y^(-4/3)\cdot \sqrt[3]{y} = y^(-1)`

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Summary:

We multiplied the coefficients to get 6.

The y terms multiply to get
`y^(-1)`

Putting all the pieces together and we get this final answer of
`6y^(-1)`

We could apply the reciprocal to the
`y^(-1)` to get 1/y; however, the instructions insist on keeping to the format
`k \cdot y^n`

In this case, k = 6 and n = -1.

A graphing calculator can be used to verify. Use x in place of y.