Final answer:
The magnitude of the vector PQ→ when P = (3, -4) and Q = (-7, 2) is approximately 11.66.
Step-by-step explanation:
To find the magnitude of a vector PQ→, we can use the distance formula. The formula for the magnitude of a vector in two dimensions is given by:
|PQ→| = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Using the given coordinates for P and Q: P(3, -4) and Q(-7, 2), we can substitute the values into the formula:
|PQ→| = sqrt((-7 - 3)^2 + (2 - (-4))^2) = sqrt((-10)^2 + (6)^2) = sqrt(100 + 36) = sqrt(136) = 11.66
The magnitude of vector PQ→ is approximately 11.66.