Final answer:
The question appears to contain a typo in the conversion from L/min to dynes/sec/-5. To convert L/min to m³/s, a conversion factor of 10⁻³ m³/L and 1 min/60 s is used, but the question does not provide enough detail to complete the conversion to dynes.
Step-by-step explanation:
The conversion factor used to change L/min to dynes/sec/-5 looks like it includes a typo because dynes/sec is a unit of force over time, and the '/-5' doesn't appear to correspond to a standard unit or conversion. However, considering the rest of the question, we can calculate the conversion factor by analyzing units of volume (L) and time (min) related to a physics concept. The passage provided refers to a calculation based on Bernoulli's Equation, where it converts L/min to cubic meters per second (m³/s) using a conversion factor of 10⁻³ m³/L (to convert liters to cubic meters) and 1 min/60 s (to convert minutes to seconds). These two conversion factors are multiplied together to get the conversion from L/min to m³/s. To convert to dynes, additional steps involving fluid mechanics principles are required, which are not fully outlined in the question.