Using the trigonometric ratios we found the value of cos L to be √43 / 22 and the value of sin K to be √43 / 22.
As we can see in the figure that we are given a right angle triangle KJL , right angled at J , where JL = √43 JK = 21 and KL = 22.
We are asked to find the value of cosL and sin K.
So,
Let us consider angle L as angle of reference (theta).
cos theta = base / hypotenuse
Here is theta is L.
cos L = JL / KL
cos L = √43 / 22
So , the value of cos L is going to be √43 / 22.
Now , we need to find the value of sin K.
Take angle K as angle reference now so in order to that hypotenuse is going to be KL perpendicular is going to JL and base is going to be JK.
sin theta = perpendicular / hypotenuse
Here is theta is K.
sin K = JL / KL
sin K = √43 / 22
So , the value of sin K is also going to be √43 / 22 .