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A Carnot engine operates between two reservoirs with unknown temperatures. If the Carnot engine operates at 67% efficiency, what is the ratio of the absolute temperatures of the reservoirs, Tc/Th?

A) 0.0025
B) 0.33
C) 0.0012
D) 0.67

User Rmv
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1 Answer

4 votes

Final answer:

The ratio of the absolute temperatures (Tc/Th) for a Carnot engine operating at 67% efficiency is 0.33, which corresponds to answer choice B.

Step-by-step explanation:

If a Carnot engine operates at 67% efficiency, we can find the ratio of the absolute temperatures of the reservoirs by using the formula for Carnot efficiency, which states Efficiency (e) = 1 - (Tc/Th). Since the efficiency is given as 0.67, or 67%, we can rearrange the formula to solve for Tc/Th:

0.67 = 1 - (Tc/Th)

Tc/Th = 1 - 0.67

Tc/Th = 0.33

Therefore, the correct answer to the question is B) 0.33, which represents the ratio Tc/Th for a Carnot engine operating between two reservoirs with this level of efficiency.

User Mike Grace
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