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Given that P(A ∪ B) = 0.76 and P(A ∪ B') = 0.87,
find P(A).

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Final answer:

To find P(A), one would typically use the relationship P(A ∪ B) = P(A) + P(B) - P(A ∨ B), but the question lacks enough information to solve for P(A) as it does not provide P(A ∨ B), P(B), or specify the relationship between A and B.

Step-by-step explanation:

The student is asking to find the probability of P(A) given the probabilities P(A ∪ B) = 0.76 and P(A ∪ B') = 0.87. To solve for P(A), we can use the properties of probabilities involving union and complement of two events. According to the formula, P(A ∪ B) = P(A) + P(B) - P(A ∨ B).

Since we have P(A ∪ B) and P(A ∪ B'), and we know that P(A ∪ B') is equal to P(A) because B and B' are complements and thus P(B') is equal to 1 - P(B); we can set up the following system of equations:


  • P(A ∪ B) = P(A) + P(B) - P(A ∨ B) = 0.76

  • P(A ∪ B’) = P(A) + P(B') - P(A ∨ B’) = 0.87

Where P(A ∨ B’) = 0 since A and B' cannot occur at the same time. From the second equation, since P(A ∨ B’) = 0, it simplifies to P(A) + P(B') = 0.87. Thus, P(A) = 0.87 - P(B'). Given that P(B') = 1 - P(B) and since we have P(A ∪ B) = 0.76, we can also find P(B) by rearranging P(A ∪ B) as P(B) = P(A ∪ B) - P(A) + P(A ∨ B). By substituting P(B) back in the equation for P(A) in terms of P(B'), we can solve for P(A).

However, because we are not given P(A ∨ B), P(B), or P(B’) and have no additional information to determine these values or their relationships, we cannot definitively solve for P(A) based on the information provided alone. We need more information about the relationship between A and B, such as if they are independent or mutually exclusive, or specific values for P(A ∨ B) or P(B).

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