Question

I need help plzzzzz on thisisisjdsj math problem

Answer 1

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Here's the solution ~

Let's consider two points (-2 , 0) and (0 , 2) on the line to find the slope (m) :

`\qquad \sf  \dashrightarrow \: m = (y_2 - y_1)/(x_2 - x _1)`

`\qquad \sf  \dashrightarrow \: m = (2 - 0)/(0 - ( - 2))`

`\qquad \sf  \dashrightarrow \: m = (2)/(2)`

`\qquad \sf  \dashrightarrow \: m = 1`

And, now let's observe the graph ; the distance of origin (sign included) from the point where the line cuts y - axis will be the y - intercept (c) .

That is : 2 - 0 = 2 units

Next step :

As we know any line can be expressed through slope intercept form ;

`\qquad \sf  \dashrightarrow \: y = mx + c`

Here, m = slope and c = y - intercept [ already got the values ]

Now, use the values to find the equation ;

`\qquad \sf  \dashrightarrow \: y = (1 * x) + 2`

`\qquad \sf  \dashrightarrow \: y = x + 2`

Therefore the required equation is ~

`\large \qquad \qquad \sf \boxed{\boxed{ \sf y = x + 2}}`