Question

What is wrong with the following code?

int f1( int x, int y)
{
x = y *y;
return x;
int f2 ( float a, float* b )
{
if (a < b* )
*b = a
else
a = *b
return;
}
}
(A) Neither function should return a value
B) In f2, a cannot be assigned *b.
C) Both parameters to f2 should mimic pass-by reference and be pointers.
D) Nothing is wrong
E) Function definitions may not be nested

Answer 1

The code has several issues: f2 has syntax errors, including a dereferencing error and missing semicolons, missing return type, and the fact that functions cannot be nested as per standard C/C++ rules.

Step-by-step explanation:

The code provided has a few errors that need to be addressed. Let's evaluate each function separately.

For the first function f1, there doesn't seem to be any syntactical issues. It takes two int parameters, and returns an int which is a standard operation for a function. Thus, there is nothing inherently wrong with the first function as per the provided code snippet.

However, the second function f2 does have some mistakes. Firstly, there is a missing semicolon at the end of the assignment statements. Secondly, the if condition is syntactically incorrect as it uses 'b*' which is not a valid way to dereference a pointer; it should be '*b'. Lastly, the function should return a value or be of void type, but the return type is not specified at all. Moreover, nested function definitions are not allowed in standard C or C++. Each function must be defined separately.