Question

write the slope-intercept form of the equation of the line described. Through (-2,-4), Parallel to y=-3

Answer 1

To find the equation of a line parallel to
`\(y = -3\)` and passing through the point
`(-2, -4)`, we can use the fact that parallel lines have the same slope. The given line
`\(y = -3\)` has a slope
`(\(m\))` of -3.

Now, using the point-slope form of the equation
`\((y - y_1) = m(x - x_1)\)`, where
`\((x_1, y_1)\)` is a point on the line and
`\(m\)` is the slope, substitute the values:

`\[(y - (-4)) = -3(x - (-2))\]`

Simplify the equation:

`\[y = -3x - 10\]`

Now, convert it to the slope-intercept form
`(\(y = mx + b\))`:

`\[y = -3x - 10\]`

So, the slope-intercept form of the equation for the line parallel to
`\(y = -3\)` and passing through
`(-2, -4)` is
`\(y = -3x - 10\)`.