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(1) 3x²+x+10= 5x-8
(2) r^2-36r
(3) 6t^2-17t=14

Factoring polynomial

User Pabloks
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1 Answer

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Final answer:

Factored polynomial:

(1) 3x²+x+10= 5x-8 : 3x² - 4x + 18 = 0 { This quadratic equation cannot be factored further into linear factors.}

(2) r^2-36r : r = 0 or r = 36.

(3) 6t^2-17t=14 : t = 7/2 or t = -2/3.

Step-by-step explanation:

To factor the given polynomials, we need to find the common factors of the terms and group them together. Let's solve each equation step by step:

(1) 3x² + x + 10 = 5x - 8

Subtracting 5x and adding 8 to both sides, we get:

3x² - 5x + x + 10 + 8 = 0

Combining like terms, we have:

3x² - 4x + 18 = 0

This quadratic equation cannot be factored further into linear factors.

(2) r² - 36r = 0

Factoring out r from both terms, we get:

r(r - 36) = 0

Setting each factor equal to zero and solving for r, we have:

r = 0 or r - 36 = 0

Therefore, r = 0 or r = 36.

(3) 6t² - 17t = 14

Subtracting 14 from both sides, we get:

6t² - 17t - 14 = 0

Factoring the quadratic equation, we have:

(2t - 7)(3t + 2) = 0

Setting each factor equal to zero, we find:

2t - 7 = 0 or 3t + 2 = 0

Therefore, t = 7/2 or t = -2/3.

User Davlog
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