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(2x^2 +9x 5)/(x+ 2) quotient and remainder

User Populus
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Answer:

To find the quotient and remainder for the polynomial \( \frac{2x^2 + 9x + 5}{x + 2} \), you can use polynomial long division.

Let's go through the steps:

1. Divide the leading term of the numerator by the leading term of the denominator. In this case, \( \frac{2x^2}{x} = 2x \).

2. Multiply the entire denominator by the result from step 1 and subtract it from the numerator. You get \( 2x^2 + 4x \).

3. Bring down the next term from the numerator, which is \( 9x \).

4. Repeat steps 1-3 until you can't divide anymore.

The quotient is \( 2x + 5 \) and the remainder is \( -5 \). Therefore, the division is \( 2x + 5 - \frac{5}{x+2} \).

User Adamax
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