Question

(2x^2+9x 5)/(x+2) Divide

Answer 1

To divide the expression (2x^2+9x+5) by (x+2), use long division. Therefore, the division of (2x^2+9x+5)/(x+2) is equal to 2x + 5.

Step-by-step explanation:

To divide the expression (2x^2+9x+5) by (x+2), we can use long division. Here are the steps:

1. Divide the first term of the dividend (2x^2) by the first term of the divisor (x). This gives us 2x as the quotient.
2. Multiply the divisor (x+2) by the quotient (2x), giving us 2x(x+2) = 2x^2 + 4x.
3. Subtract this product from the dividend (2x^2+9x+5 - 2x^2 -4x = 5x + 5).
4. Bring down the next term from the dividend, which is 5.
5. Divide the new expression (5x + 5) by the divisor (x+2) again. This gives us 5 as the new quotient.
6. Multiply the divisor (x+2) by the new quotient (5), giving us 5(x+2) = 5x + 10.
7. Subtract this product from the new expression (5x + 5 - 5x - 10)
8. The remainder is 0.

Therefore, the division of (2x^2+9x+5)/(x+2) is equal to 2x + 5.