Question

At 46°C and 0.880 atm pressure, a gas occupies a volume of 0.600 L. How many liters will it occupy at 0°C and 0.205 atm?

A. 0.600 L
B. 0.140 L
C. 2.20 L
D. 2.58 L
E. 0.513 L

Answer 1

C.) v=2.20L

Step-by-step explanation:

According to the Combined Gas Law:

`(p_1v_1)/(t_1)=(p_2v_2)/(t_2)`

For this problem, let

`p_1=0.880atm\\v_1=0.600L\\t_1=(46+273)K=319K\\\\p_2=0.205atm\\t_2=(0+273)K=273K`

So,

`((0.880atm)(0.600L))/(319K)=((0.205atm)v_2)/(273K)\\0.00166(atm*L)/(K)=((0.205atm)v_2)/(273K)\\(0.00166(atm*L)/(K))(273K)=(((0.205atm)v_2)/(273K))(273K)\\0.452atm*L=(0.205atm)v_2\\(0.452atm*L)/(0.205atm)=((0.205atm)v_2)/(0.205atm)\\2.20L=v_2`