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How to develop this : (5x-2)²-(-2x+3)²

User CramerTV
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1 Answer

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19 votes

Answer:

21x² -8x -5

Explanation:

You want to develop (5x-2)²-(-2x+3)².

Difference of squares

The pattern for the factoring of the difference of squares is ...

a² -b² = (a -b)(a +b)

Your expression matches this with ...

a = 5x-2

b = -2x+3

So, the factoring is ...

(a -b)(a +b) = ((5x -2) -(-2x +3))·((5x -2) +(-2x +3))

= (5x +2x -2 -3)(5x -2x -2 +3)

= (7x -5)(3x +1)

This product can be found using the distributive property:

= 7x(3x +1) -5(3x +1) = 21x² +7x -15x -5

= 21x² -8x -5

Perfect square trinomial

The pattern for the square of a binomial is ...

(a +b)² = a² +2ab +b²

In the left square, you have ...

  • a = 5x
  • b = -2

so the square is ...

(5x)² +2(5x)(-2) +(-2)² = 25x² -20x +4

In the right square, you have ...

  • a = -2x
  • b = 3

so the square is ...

(-2x)² +2(-2x)(3) +(3)² = 4x² -12x +9

Then the difference of the squares is ...

(25x² -20x +4) -(4x² -12x +9) = (25 -4)x² +(-20 +12)x +(4 -9)

= 21x² -8x -5

User Nishad Up
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